This question is from trigonometry topic – trigonometric ratios on complementary angles in which we have been asked to prove that cosec(67°+θ) – sec(23°-θ) = 0
RS Aggarwal, Class 10, chapter 12, question no 7(iii)
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LHS
= cosec (67° + θ) – sec (23° – θ)
= cosec (67° + θ) – sec (90° – (23° + θ)) = cosec (67° + θ) – cosec (67° + θ)
= 0 = RHS proved