This is arithmetic progression based question from Chapter name- Arithmetic Progression
Chapter number- 9
Exercise – 9.1
In this question we have been given the nth term (n-2)/3 of an arithmetic series and we have to find the first term of the series.
CBSE DHANPAT RAI PUBLICATIONS
Understanding CBSE Mathematics
Class :- 10th
Question no 1 (ii )
Given:
By putting n = 1, 2, 3, 4, 5 we get first five term of the sequence
an = (n – 2)/3
a1 = (1-2)/3 = -1/3
a2 = (2 – 2)/3 = 0
a3 = (3 – 2)/3 = 1/3
a4 = (4 – 2)/3 = 2/3
a5 = (5 – 2)/3 = 3/3 =1
∴ The first five terms are -1/3, 0, 1/3, 2/3, 1