CBSE 10th Class Mathematics
Past year question paper
Year 2020
SET 1, Code Number – 30/5/1
Question Number – 24 [b]
perimeter problem
triangle perimeter
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Perimeter of ΔABC = AB + BC + AC
= AB + BD + CD + AC
= AB + BP + CQ + AC
[Since BD = BP and CD = CQ]
= AP + AQ
= 2AP [AP = AQ, Tangents drawn
from external point]
= 2 × 12
= 24 cm