One of the basic question from similarity chapter in which we have been asked to find the length of sides PY and XY by using the properties of similarities
ML Aggarwal Avichal Publication, Similarity, class 10, chapterv13ii, question no 1c
Lost your password? Please enter your email address. You will receive a link and will create a new password via email.
From the figure,
XY∥QR,PX=1cm,QX=3 cm, YR=4.5 cm and QR=9 cm,
So, PX/QX=PY/YR
1/3=PY/4.5
By cross multiplication we get,
(4.5×1)/3=PY
PY=45/30
PY=1.5
Then, ∠X=∠Q
∠Y=∠R
So, ∠PXY∼△PQR
Therefore, XY/QR=PX/PQ
XY/9=1/(1+3)
XY/9=1/4
XY=9/4
XY=2.25.