The best way to solve the problem of triangles of exercise 6.2 of class 10th math, how i solve this question because it is very important for board exams In the figure, DE||AC and DF||AE. Prove that BF/FE = BE/EC
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In ΔABC, given as, DE || AC
Thus, by using Basic Proportionality Theorem, we get,
∴BD/DA = BE/EC ………………………………………………(i)
In ΔABC, given as, DF || AE
Thus, by using Basic Proportionality Theorem, we get,
∴BD/DA = BF/FE ………………………………………………(ii)
From equation (i) and (ii), we get
BE/EC = BF/FE
Hence, proved.