In class 10th math subject i don’t know how to solve the problem of triangles of exercise 6.3 of question no.7(2) please help to guide the answer In the figure, altitudes AD and CE of ΔABC intersect each other at the point P. Show that:(ii) ΔABD ~ ΔCBE
AnilSinghBoraGuru
In the figure, altitudes AD and CE of ΔABC intersect each other at the point P. Show that:(ii) ΔABD ~ ΔCBE Q.7(2)
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In ΔABD and ΔCBE,
∠ADB = ∠CEB ( 90° each)
∠ABD = ∠CBE (Common Angles)
Hence, by AA similarity criterion,
ΔABD ~ ΔCBE