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In the figure, altitudes AD and CE of ΔABC intersect each other at the point P. Show that:(i) ΔAEP ~ ΔCDP Q.7

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How i solve the first part of the question of 7 of exercise 6.3 of chapter triangles of class 10th math, please suggest me the best way to solve this question In the figure, altitudes AD and CE of ΔABC intersect each other at the point P. Show that:(i) ΔAEP ~ ΔCDP

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  1. In ΔAEP and ΔCDP,

    ∠AEP = ∠CDP (90° each)

    ∠APE = ∠CPD (Vertically opposite angles)

    Hence, by AA similarity criterion,

    ΔAEP ~ ΔCDP

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