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Deepak Bora
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In the given figure, DE || AC and DF || AE Prove that BF/BE = FE/EC

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CBSE 10th Class Mathematics
Past year question paper
Year 2020
SET 1, Code Number  – 30/5/1
Question Number –  21
parallel theorem
prove by help of tringle area

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1 Answer

  1. Given DE || AC
    In ΔABC-

    BE/EC = BD/AD         [1]

    AND DE ll AC

    In ΔBEA –

    BF/FE = BD/AD       [2]

    From [1] AND [2]

    BE/EC = BF/FE

    Hence proved.

     

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