(i) In this question we have been asked to prove that from the given figure two triangles are similar
(ii) In the given question we are asked to calculate the length of sides of triangle
ML Aggarwal Avichal Publication, Similarity, question no 8(b)
(i) We have to prove that, △ACO∼△BDO.
So, from the figure
Consider △ACO and △BDO
Then,
∠AOC=∠BOD [from vertically opposite angles]
∠A=∠B
Therefore, △ACO=△BDO
Given, BD=2.4 cm,OD=4 cm,OB=3.2 cm,AC=3.6 cm,
△ACO∼△BOD
So, AO/OB=CO/OD=AC/BD
Consider AC/BD=AO/OB
3.6/2.4=AO/3.2
O=(3.6×3.2)/2.4
AO=4.8cm
Now, consider AC/BD=CO/OD
3.6/2.4=CO/4
CO=(3.6×4)/2.4
CO=6cm.