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AnilSinghBora
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Asked: 2021-07-16T17:09:39+05:30 In:

In the fig.6.36, QR/QS = QT/PR and ∠1 = ∠2. Show that ΔPQS ~ ΔTQR. Q.4

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In the fig.6.36, QR/QS = QT/PR and ∠1 = ∠2. Show that ΔPQS ~ ΔTQR. Q.4

For class 10th students, of chapter triangles exercise 6.3, this is very tough question so please help to solve this question in easy way In the fig.6.36, QR/QS = QT/PR and ∠1 = ∠2. Show that ΔPQS ~ ΔTQR

best math solutionexercise 6.3 ncertncert class 10th solutiontriangles ncert
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    1. Guru

      In ΔPQR,

      ∠PQR = ∠PRQ

      ∴ PQ = PR ………………………(i)

      Given,

      QR/QS = QT/PRUsing equation (i), we get

      QR/QS = QT/QP……………….(ii)

      In ΔPQS and ΔTQR, by equation (ii),

      QR/QS = QT/QP

      ∠Q = ∠Q

      ∴ ΔPQS ~ ΔTQR [By SAS similarity criterion]

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