CBSE 10th Class past year question paper
Year 2019
SET 1, Code Number- 30/2/1
Question number – 18 (b)
Deepak BoraNewbie
In Figure 5, ABCD is a square with side 2 √2 cm and inscribed in a circle. Find the area of the shaded region. (Use π = 3·14)
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BD = √{ (2 √2)² + (2 √2)² }
= 4 cm
∴ Radius of circle = 2 cm
∴ Shaded area = Area of circle – Area of square
= 3.14 × 2² − (2 √2)²
= 12.56 – 8
= 4.56 cm²