Question drawn from very renowned book RD sharma of class 10th, Chapter no. 4
Chapter name:- Triangles
Exercise :- 4.3
This is very important question of triangle.
It is given that In ∆ABC,
AD is the bisector of ∠A, meeting side BC at D.
Also we have been given sides AB = 5.6 cm, AC = 6 cm and DC = 3 cm,
Now we have to find BC
learning CBSE maths in efficient way
RD sharma, DHANPAT RAI publication
Class 10th, triangle
Since, AD is the bisector of ∠ A meeting side BC at D in Δ ABC
⇒ AB/ AC = BD/ DC
5.6/ 6 = BD/ 3
BD = 5.6/ 2 = 2.8cm
And, we know that,
BD = BC – DC
2.8 = BC – 3
∴ BC = 5.8 cm