Question drawn from very renowned book RD sharma of class 10th, Chapter no. 4
Chapter name:- Triangles
Exercise :- 4.3
This is very important question based on triangle fundamental properties.
In this question we have In a ∆ABC, AD is the bisector of ∠A, meeting side BC at D.
Also the sides measurements are given AC = 4.2 cm, DC = 6 cm and BC = 10 cm,
Now we have to find AB
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RD sharma, DHANPAT RAI publication
Class 10th, triangle
Since, AD is the bisector of ∠ A meeting side BC at D in Δ ABC
⇒ AB/ AC = BD/ DC
AB/ 4.2 = BD/ 6
We know that,
BD = BC – DC = 10 – 6 = 4 cm
⇒ AB/ 4.2 = 4/ 6
AB = (2 x 4.2)/ 3
∴ AB = 2.8 cm