This is the basic and conceptual question from trigonometric ratios in which we have given x=cosecA+cosA and y=cosecA−cosA and we have to prove that [2/(x+y)]^2 + [(x−y)/2]^2 −1=0.
RS Aggarwal, Class 10, chapter 10, question no 34.
Rajan@2021Guru
If x=cosecA+cosA and y=cosecA−cosA then prove that [2/(x+y)]^2 + [(x−y)/2]^2 −1=0.
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