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Rajan@2021
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Asked: 2021-04-05T17:57:17+05:30 In:

If A = 45° verify that sin 2A = 2sin A cos A

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This is the basic and conceptual question from trigonometric ratios in which we have given A = 45°

We have been asked to prove that sin 2A = 2sin A cos A

RS Aggarwal, class 10, chapter 11, question no 12(i).

class 10 cbsers aggarwaltrigonometric ratios
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      A=45∘ then 2A=90∘

      sin2A = sin90∘

      RHS

      2sinAcosB
      =2sin45∘ cos45∘
      =2×1/√2​×1/√2​

      2sinAcosB = 1

      LHS:

      sin90∘=1

      L.H.S.=R.H.S.

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