We have asked to find the perimeter of triangle using similarity if△ABC∼△DEF,AB=4 cm,DE=6 cm,EF=9 cm and FD=12 cm.
ML Aggarwal Avichal publication, Similarity chapter 13, question no 6
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AB = 4 cm, DE = 6 cm EF = 9 cm FD = 12 cm Also, ∆ABC ∼ ∆DEF We have, And by taking last two terms, we have, Now, Perimeter of ∆ABC = AB + BC + AC = 4 + 6 + 8 = 18 cm Thus, the perimeter of the triangle is 18.