Give me the best way for solving the question of class 9th of Surface areas and Volumes of exercise 13.2 of math. Give me the easiest way for solving this question in simple way of question no.9(2) Find(ii) How much steel was actually used, if 1/12 of the steel actually used was wasted in making the tank. (Assume π = 22/7)
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Find(ii) How much steel was actually used, if 1/12 of the steel actually used was wasted in making the tank. (Assume π = 22/7) Q.9(2)
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Total surface area of tank = 2πr(r+h)
= 2×(22/7)×2.1×(2.1+4.5)
= 44×0.3×6.6
= 87.12 m2
Now, Let S m2 steel sheet be actually used in making the tank.
S(1 -1/12) = 87.12 m2
This implies, S = 95.04 m2
Therefore, 95.04m2 steel was used in actual while making such a tank.