Adv
Deepak Bora
  • 1
Newbie

Find the zeroes of the quadratic polynomial 7y² – 11/3 y – 2/3 and verify the relationship between the zeroes and the coefficients.

  • 1

CBSE 10th Class past year question paper

Year 2019

SET 1, Code Number- 30/2/1

Question number – 21 (b)

Share

1 Answer

  1. p(y) = 7y² – (11/3)y – 2/3

    = 1/3 (21y² – 11y – 2)

    = 1/3 [(7 y 1)(3y – 2)]

    ∴ Zeroes are 2/3, –1/7

    Sum of zeroes =(2/3) – ( 1/7)

    = -2/21

    -b/a = 11/21

    ∴ sum of zeroes = -b/a

    Product of zeroes = (2/3) – ( 1/7)
    = – 2/21
    c/a = – (2/3) (1/7)

    = – 2/21
    ∴ Product =c/a

    • 0
Leave an answer

Leave an answer

Browse

Choose from here the video type.

Put Video ID here: https://www.youtube.com/watch?v=sdUUx5FdySs Ex: "sdUUx5FdySs".

Captcha Click on image to update the captcha.

Related Questions