An Important Question of class 10 Based on Equation of a Straight Line Chapter of M.L Aggarwal for ICSE BOARD.
Here a point is given through which a line is passing and also having x-intercept
So, you have to find the equation of the line.
This is the Question Number 24, Exercise 12.1 of M.L Aggarwal.
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Find the equation of a line passing through the point (– 2, 3) and having x-intercept 4 units.
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Given, point (-2, 3) and the x-intercept of the line passing through that point is 4 units.
So, the co-ordinates of the point where the line meets the x-axis is (4, 0)
Now, slope of the line passing through the points (-2, 3) and (4, 0)
m = y2 – y1/ x2 – x1
m = (0 – 3)/(4 + 2) = -3/6 = -1/2
Hence, the equation of the line will be
y – y1 = m (x – x1)
y – 0 = -½ (x – 4)
2y = -x + 4
⇒ x + 2y = 4