An important and exam oriented question from arithmetic progression chapter as it was already asked in previous year paper of 2017 in which we are to find the number of integers divisibile by 8 between 200 and 500.
Book – RS Aggarwal, class 10, chapter 5A, question no 48
We have,
200,208,216.......496
∴Tn=496
a+(n−1)d=496
200+(n−1)d=496
200+8n−8=496
8n+192=496
8n=496−192
8n=304
n=304/8
n=38
Hence, 38 integers are divisible by 8 between 200 and 500.