Yesterday i was doing the question from class 9th ncert book of math of Polynomials chapter of exercise 2.5. What is the easiest way for solving it because i was not able to do this question please help me for solving this question Factorize each of the following: (i) 27y3+125z3
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The expression, 27y3+125z3 can be written as (3y)3+(5z)3
27y3+125z3 = (3y)3+(5z)3
We know that, x3+y3 = (x+y)(x2–xy+y2)
27y3+125z3 = (3y)3+(5z)3
= (3y+5z)[(3y)2–(3y)(5z)+(5z)2]
= (3y+5z)(9y2–15yz+25z2)