Hello sir give me the best way for solving the problem of Polynomials chapter of exercise 2.5 of math of question no.4(2) how i solve this question in simple way give me the best way for solving this question. Expand each of the following, using suitable identities:(ii) (2x−y+z)2
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Using identity, (x+y+z)2 = x2+y2+z2+2xy+2yz+2zx
Here, x = 2x
y = −y
z = z
(2x−y+z)2 = (2x)2+(−y)2+z2+(2×2x×−y)+(2×−y×z)+(2×z×2x)
= 4x2+y2+z2–4xy–2yz+4xz