Give me the best way for solving the problem of question no.2(3) of Polynomials chapter of exercise 2.5 of class 9th give me the tricky way for solving this question Evaluate the following products without multiplying directly:(iii) 104×96
AnilSinghBoraGuru
Evaluate the following products without multiplying directly:(iii) 104×96 Q.2(3)
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104×96 = (100+4)×(100–4)
Using identity, [(a+b)(a-b)= a2-b2]
Here, a = 100
b = 4
We get, 104×96 = (100+4)×(100–4)
= (100)2–(4)2
= 10000–16
= 9984