What is the best way for solving the problem of class 9th ncert of Polynomials chapter of exercise 2.5 of math. Give me the simple way for solving this question i think it is very important question for class 9th Evaluate the following products without multiplying directly: (i) 103×107
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Evaluate the following products without multiplying directly: (i) 103×107 Q.2(1)
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103×107= (100+3)×(100+7)
Using identity, [(x+a)(x+b) = x2+(a+b)x+ab
Here, x = 100
a = 3
b = 7
We get, 103×107 = (100+3)×(100+7)
= (100)2+(3+7)100+(3×7))
= 10000+1000+21
= 11021