Please give me the best way for solving the problem of class 9th ncert math of Surface areas and Volumes chapter of math of class 9th of exercise 13.2 of question no 6 what is the tricky way for solving this question Curved surface area of a right circular cylinder is 4.4 m2. If the radius of the base of the base of the cylinder is 0.7 m, find its height. (Assume π = 22/7)
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Curved surface area of a right circular cylinder is 4.4 m2. If the radius of the base of the base of the cylinder is 0.7 m, find its height. (Assume π = 22/7) Q.6
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Let h be the height of the circular cylinder and r be the radius.
Radius of the base of cylinder, r = 0.7m
CSA of cylinder = 2πrh
CSA of cylinder = 4.4m2
Equating both the equations, we have
2×(22/7)×0.7×h = 4.4
Or h = 1
Therefore, the height of the cylinder is 1 m.