Hello sir i want to know the best solution of the question from exercise 13.3 of math of Surface areas and Volumes chapter of class 9th give me the best and easy for solving this question how i solve it of question no. 7 A joker’s cap is in the form of right circular cone of base radius 7 cm and height 24cm. Find the area of the sheet required to make 10 such caps. (Assume π =22/7)
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A joker’s cap is in the form of right circular cone of base radius 7 cm and height 24cm. Find the area of the sheet required to make 10 such caps. (Assume π =22/7) Q.7
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Radius of conical cap, r = 7 cm
Height of conical cap, h = 24cm
Slant height, l2 = (r2+h2)
= (72+242)
= (49+576)
= (625)
Or l = 25 cm
CSA of 1 conical cap = πrl
= (22/7)×7×25
= 550
CSA of 10 caps = (10×550) cm2 = 5500 cm2
Therefore, the area of the sheet required to make 10 such caps is 5500 cm2.