ICSE Board Question Based on Mensuration Chapter of M.L Aggarwal for class10
In this question a hemispherical brass bowl inner- diameter is given.
Find the cost of tin-plating it on the inside at the rate of Rs 16 per 100 cm square.
This is the Question Number 07, Exercise 17.3 of M.L Aggarwal.
Deepak BoraNewbie
A hemispherical brass bowl has inner- diameter 10.5 cm. Find the cost of tin-plating it on the inside at the rate of Rs 16 per 100 cm square.
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Given inner diameter of the brass bowl, d = 10.5 cm
Radius, r = d/2 = 10.5/2 = 5.25 cm
Curved surface area of the bowl = 2r2
= 2×(22/7)×5.252
= 173.25 cm2
Rate of tin plating = Rs.16 per 100 cm2
So total cost = 173.25×16/100 = 27.72
Hence the cost of tin plating the bowl on the inside is Rs. 27.72.