What is the best way for solving the problem of question of 2 of exercise 15.2 of probability chapter of class 10th ncert math, please give me the best way for solving this problem A die is numbered in such a way that its faces show the numbers 1, 2, 2, 3, 3, 6. It is thrown two times and the total score in two throws is noted. Complete the following table which gives a few values of the total score on the two throws: What is the probability that the total score is (i) even? (ii) 6? (iii) at least 6?
So, the total number of outcomes = 6×6 = 36
(i) E (Even) = 18
P (Even) = 18/36 = ½
(ii) E (sum is 6) = 4
P (sum is 6) = 4/36 = 1/9
(iii) E (sum is atleast 6) = 15
P (sum is atleast 6) = 15/36 = 5/12