Solution:

Given,

2.2 dm³ of brass is to be drawn into a cylindrical wire of Diameter = 0.25 cm

So, the radius of the wire (r) = d/2

= 0.25/2 = 0.125*10^-2 cm

Now, 1 cm = 0.01 m

So, 0.1cm = 0.001 m

Let the length of the wire be (h)

We know that,

The volume of the cylinder = πr²h

It’s understood that,

The volume of cylindrical wire = The volume of brass of 2.2 dm³

h = 448 m

Therefore, the length of the cylindrical wire drawn is 448 m.