Adv
  1. AB=5cm AC=12cm BD=2.5cm BC=9=BD+DC=2.5+DC CD=6.5cm   ACAB​=125​≈0.42 (1)   CDBD​=6.52.5​≈0.38 (2)   (1)=(2)   Hence AD is not the bisector of ∠A of △ ABC

    AB=5cm

    AC=12cm

    BD=2.5cm

    BC=9=BD+DC=2.5+DC

    CD=6.5cm
     
    ACAB=1250.42 (1)
     
    CDBD=6.52.50.38 (2)

     
    (1)=(2)
     
    Hence AD is not the bisector of A of  ABC

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