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AB=5cm AC=12cm BD=2.5cm BC=9=BD+DC=2.5+DC CD=6.5cm ACAB=125≈0.42 (1) CDBD=6.52.5≈0.38 (2) (1)=(2) Hence AD is not the bisector of ∠A of △ ABC
AB=5cm
AC=12cm
BD=2.5cm
BC=9=BD+DC=2.5+DC
CD=6.5cm ACAB=125≈0.42 (1) CDBD=6.52.5≈0.38 (2) (1)=(2) Hence AD is not the bisector of ∠A of △ ABC
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Check whether AD is the bisector of ∠A of ΔABC in each of the following: AB = 5 cm, AC = 12 cm, BD = 2.5 cm and BC = 9 cm
AB=5cm AC=12cm BD=2.5cm BC=9=BD+DC=2.5+DC CD=6.5cm ACAB=125≈0.42 (1) CDBD=6.52.5≈0.38 (2) (1)=(2) Hence AD is not the bisector of ∠A of △ ABC
AB=5cm
AC=12cm
BD=2.5cm
BC=9=BD+DC=2.5+DC
CD=6.5cm
See lessACAB=125≈0.42 (1)
CDBD=6.52.5≈0.38 (2)
(1)=(2)
Hence AD is not the bisector of ∠A of △ ABC