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AnilSinghBora
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Asked: 2021-07-30T10:44:43+05:30 In:

A tangent PQ at a point P of a circle of radius 5 cm meets a line through the centre O at a point Q so that OQ = 12 cm. Length PQ is : (A) 12 cm (B) 13 cm (C) 8.5 cm (D) √119 cm Q.3

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What is the best way to solve this question of class 10th ncert of exercise 10.1 of circles chapter of question no.3, please help me to solve this question , it is an important question for class 10Th A tangent PQ at a point P of a circle of radius 5 cm meets a line through the centre O at a point Q so that OQ = 12 cm. Length PQ is : (A) 12 cm (B) 13 cm (C) 8.5 cm (D) √119 cm

best math ncert solutioncircles ncertexercise 10.1 ncertncert class 10th solution
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    1. Guru
      This answer was edited.

      Ncert solutions class 10 chapter 10-1

      In the above figure, the line that is drawn from the centre of the given circle to the tangent PQ is perpendicular to PQ.

      And so, OP ⊥ PQ

      Using Pythagoras theorem in triangle ΔOPQ we get,

      OQ2 = OP2+PQ2

      (12)2 = 52+PQ2

      PQ2 = 144-25

      PQ2 = 119

      PQ = √119 cm

      So, option D i.e. √119 cm is the length of PQ.

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