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AnilSinghBora
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The diagonal of a rectangular field is 60 metres more than the shorter side. If the longer side is 30 metres more than the shorter side, find the sides of the field. Q.6

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How i solve this question of class 10th of quadratic equation. It is very important type of question. The diagonal of a rectangular field is 60 metres more than the shorter side. If the longer side is 30 metres more than the shorter side, find the sides of the field.

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  1. Let us say, the shorter side of the rectangle be x m.

    Then, larger side of the rectangle = (x + 30) m

    Ncert solutions class 10 chapter 4-6

    As given, the length of the diagonal is = x + 30 m

    Therefore,

    Ncert solutions class 10 chapter 4-7

    ⇒ x2 + (x + 30)2 = (x + 60)2

    ⇒ x2 + x2 + 900 + 60x = x2 + 3600 + 120x

    ⇒ x2 – 60x – 2700 = 0

    ⇒ x2 – 90x + 30x – 2700 = 0

    ⇒ x(– 90) + 30(x -90) = 0

    ⇒ (– 90)(x + 30) = 0

    ⇒ = 90, -30

    However, side of the field cannot be negative. Therefore, the length of the shorter side will be 90 m.

    and the length of the larger side will be (90 + 30) m = 120 m.

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