One of the most important and exam oriented question as it was already asked in previous year paper of 2008 in which we have given that 4x-3y+4=0, 4x+3y-20=0 and we have to solve the equations graphically and also asked to find the vertices and the area of the triangle formed by these lines and the x-axis
RS Aggarwal, Class 10, chapter 3A, question no 13
4x−3y+4=0….(1)
4x+3y−20=0……(2)
Isolate x from equation (1) and find the value of x and y.
4x−3y+4=0
or x=(3y−4)/4
Similarly, isolate x from equation (2) and find the values of x and y.
4x+3y−20=0
or x=(20−3y)/4
Graph:
Both the lines intersect each other at point (2,4) and x− axis at A(−1,0) and D(5,0).
Find the area of triangle BAD:
Area of △BAD=1/2(base×altitude)
=1/2×6×4
=12 sq.units.