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Rajan@2021
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Asked: 2021-04-08T17:02:13+05:30 In:

Prove that: tan5° tan25° Tan30° tan65° tan85° = 1/√3

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This question is from trigonometry topic -trigonometric ratios on complementary angles in which we have been asked to show that cotθ tan(90°-θ) – sec(90°-θ) cosecθ + √3tan12° tan60° tan78° = 2

RS Aggarwal, Class 10, chapter 12, question no 6(i)

class 10 cbsers aggarwaltrigonometric ratios
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    1. Guru
      Prove that: tan5° tan25° Tan30° tan65° tan85° = 1/√3

      Hope it helps you.

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