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Evaluate: 2cos^2 60° + 3sin^2 45° – 3sin^2 30° + 2cos^2 90°

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This is the basic and exam oriented question from trigonometric ratios in which we have to find the value of 2cos^2 60° + 3sin^2 45° – 3sin^2 30° + 2cos^2 90°

RS Aggarwal, Class 10, chapter 11, question no 6

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