(4x² + xy )/(3xy – y²) = 12/ 5

cross multiplying

5(4x²+xy) = 12(3xy-y²)

20x² + 5xy = 36xy- 12y²

divide complete equation by xy

20x/y +5 = 36 – 12y/x

20x/y + 12y/x = 36-5

20x/y +12 y/x = 31

let x/y = a

∴ 20a+ 12/a = 31

∴ 20a² – 31a + 12 = 0

20a² -16a-15a+ 12 = 0

4a(5a-4)-3(5a-4)=0

(5a-4)(4a-3)= 0

∴ a= 4/5 & a= 3/4

because x/y = a

∴ x/y =4/5    &    x/y =3/4