Sir please give me a detailed solution of this question in which we are to find for which value of X the numbers (5x + 2), (4x – 1) and (x + 2) are in AP.
RS Aggarwal, class 10, chapter 5B, question no 2.
Rajan@2021Guru
Find the value of x for which the numbers (5x + 2), (4x – 1) and (x + 2) are in AP.
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Given: (5x+2),(4x−1) and (x+2) are terms in AP.
So, d=(4x−1)−(5x+2)=(x+2)−(4x−1)
2(4x−1)=(x+2)+(5x+2)
8x−2=6x+2+2
8x−2=6x+4
8x−6x=4+2
or x=3
The value of x is 3.