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a(x²+1)= (a²+1)x
ax² + a= (a²+1)x
ax²-(a²+1)x+a=0
Using the quadratic formula
X= -b±√b²-4ac/2a
X= -(-a²-1)±√[-(a²+1)]²-4.a.a /2a
X= a²+1±√a ^4+1+2a²-4a² /2a
X= a²+1±√a^4+1-2a² /2a
X = a²+1±√(a²-1)² /2a
X= a²+1± a²-1 /2a
∴x= a²+1+a²-1 /2a & x= a²+1-a²+1 /2a
x =a, & x= 1/a