How can i solve this tough question of class 9th ncert of Surface areas and Volumes of math of exercise 13.6 of question no.3 . Give me the best and simple way for solving this question. A soft drink is available in two packs – (i) a tin can with a rectangular base of length 5cm and width 4cm, having a height of 15 cm and (ii) a plastic cylinder with circular base of diameter 7cm and height 10cm. Which container has greater capacity and by how much? (Assume π=22/7)
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A soft drink is available in two packs – (i) a tin can with a rectangular base of length 5cm and width 4cm, having a height of 15 cm and (ii) a plastic cylinder with circular base of diameter 7cm and height 10cm. Which container has greater capacity and by how much? (Assume π=22/7) Q.3
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Dimensions of tin can are
Length, l = 5 cm
Breadth, b = 4 cm
Height, h = 15 cm
Capacity of tin can = l×b×h= (5×4×15) cm3 = 300 cm3
Dimensions of plastic can are:
Radius of circular end of plastic cylinder, r = 3.5cm
Height , H = 10 cm
Capacity of plastic cylinder = πr2H
Capacity of plastic cylinder = (22/7)×(3.5)2×10 = 385
Capacity of plastic cylinder is 385 cm3
From results of (i) and (ii), plastic cylinder has more capacity.
Difference in capacity = (385-300) cm3 = 85cm3