what is the tricky way for solving the question of class 9th ncert math of Surface areas and Volumes chapter of ncert of exercise 13.2 of math give me the best and simple way for solving this question in easy and simple way of question no. 7(2) The inner diameter of a circular well is 3.5m. It is 10m deep. Find (ii) the cost of plastering this curved surface at the rate of Rs. 40 per m2. (Assume π = 22/7)
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The inner diameter of a circular well is 3.5m. It is 10m deep. Find (ii) the cost of plastering this curved surface at the rate of Rs. 40 per m2. (Assume π = 22/7) Q.7(2)
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Cost of plastering 1 m2 area = Rs.40
Cost of plastering 110 m2 area = Rs (110×40)
= Rs.4400
Therefore, the cost of plastering the curved surface of the well is Rs. 4400.