What is the best way for solving the question from class 9th ncert math of Polynomials chapter of Ncert of exercise 2.5 of math. What is the best way for solving this question please guide me the best way for solving this question. Evaluate the following using suitable identities: (ii) (102)3
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We can write 102 as 100+2
Using identity,(x+y)3 = x3+y3+3xy(x+y)
(100+2)3 =(100)3+23+(3×100×2)(100+2)
= 1000000 + 8 + 600(100 + 2)
= 1000000 + 8 + 60000 + 1200
= 1061208