How i solve this tough question of class 9th ncert book of chapter Polynomials of exercise 2.4 of math. I don’t know how to solve this problem Please give me the best way for solving this question Find the value of k, if x–1 is a factor of p(x) in each of the following cases: (i) p(x) = x2+x+k
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Find the value of k, if x–1 is a factor of p(x) in each of the following cases: (i) p(x) = x2+x+k Q.3(1)
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If x-1 is a factor of p(x), then p(1) = 0
By Factor Theorem
⇒ (1)2+(1)+k = 0
⇒ 1+1+k = 0
⇒ 2+k = 0
⇒ k = −2