What is the best and easy way for solving the problem of class 9th ncert book of math of Polynomials chapter of exercise 2.4, give me the tricky solution of this question Use the Factor Theorem to determine whether g(x) is a factor of p(x) in each of the following cases:(iii) p(x)=x3–4×2+x+6, g(x) = x–3
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Use the Factor Theorem to determine whether g(x) is a factor of p(x) in each of the following cases:(iii) p(x)=x3–4×2+x+6, g(x) = x–3 Q.2(3)
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p(x) = x3–4x2+x+6, g(x) = x -3
g(x) = 0
⇒ x−3 = 0
⇒ x = 3
∴ Zero of g(x) is 3.
Now,
p(3) = (3)3−4(3)2+(3)+6
= 27−36+3+6
= 0
∴By factor theorem, g(x) is a factor of p(x).