In this Question you have to find the next term of the given AP.

This is the Important question based on Arithmetic progression Chapter of R.S Aggarwal book for ICSE & CBSE

Board.

This is the Question Number 8 Of Exercise 11 D of RS Aggarwal Solution.

# Write the next term of the AP √8,√18,√32,……..

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√8=√4×2=2√2

√18=√9×2=3√2

√32=√16×2=4√2

therefore next term will be,

5√2=√25×2=√50

and next root is

6√2=√36×2=√72

it continues till infinity

I will say u how I had done this method

see this is A.P

just take first term

√8 u take it and divide this √8

see properly

√(4×2)=√8

u can do like this

so, here

√4x√2=√8

u can take like also write

so now the

2x√2

therefore √4= 2

so u got this as 2√2=√8

so take next term

and try to do in these methods only so u can get it

and this is arithmetic progression so now u have to find next term

2√2,3√2,4√2,…

so there is a common difference

d=a2-a1

d=√2

so,

and next term will be 5√2