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Rajan@2021
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Without using trigonometric tables, prove that: sin35°sin55° – cos35°cos55° = 0

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This question is from trigonometry

topic – trigonometric ratios on complementary angles

We have been asked to prove that sin35°sin55° – cos35°cos55° = 0 without using trigonometric tables

RS Aggarwal, class 10, chapter 12, question no 3(iv)

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  1. We know that,  sin (90 – θ) = cos θ  So, the given can be expressed as  sin (90 – 55)° sin (90 – 35)° – cos 35° cos 55°

    = cos 55° cos 35° – cos 35° cos 55°

    = 0

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