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Rajan@2021
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The sum of first three terms of an AP is 48. If the product of first and second terms exceeds 4 times the third term by 12. Find the AP.

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One of the basic question from arithmetic progression chapter in which the product of first and second terms exceeds 4 times the third term by 12 and the sum of first three terms is 48. We have to the AP.

Book – RS Aggarwal, Class 10, chapter 5B, question no 13.

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1 Answer

  1. Let ad,a,a+d are the three terms of AP
    So,
    Sum=ad+a+a+d=48
    3a=48
    or a=16
    And,
    a(ad)=4(a+d)+12
    16(16d)=4(16+d)+12
    25616d=64+4d+12=4d+76
    25676=4d+16d
    180=20d
    d=9
    Which implies:
    Numbers are: (7,16,25).

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