An important and conceptual question from real numbers chapter in which we have given a number 161 and we have been asked to find the other number if their HCF is 23 and their LCM is 1449.

Kindly provide me a detailed solution of this question

RS Aggarwal, Class 10, chapter 1B, question 3

Given,Â HCF=23

LCM=1449

Let the two numbers beÂ aÂ andÂ b. LetÂ a=161. We have to findÂ b.

We know that

HCF(a,b)Ã—LCM(a,b)=aÃ—b

â‡’23Ã—1449=161Ã—b

â‡’23Ã—1449â€‹/161=b

â‡’b=23Ã—9

âˆ´b=207

Thus, the other number isÂ 207.