An important question from RS Aggarwal, Chapter- Linear equations in which we have given the equations x-y+3=0, 2x+3y-4=0 And we have to solve the equations graphically and also we asked to find the vertices and the area of the triangle formed by these lines and the x-axis
Kindly solve the problem
Chapter 3A, question no 11
x−y+3=0….(1)
2x+3y−4=0……(2)
Isolate x from equation (1) and find the value of x and y.
x−y+3=0
or x=y−3
Similarly, isolate x from equation (2) and find the values of x and y.
2x+3y−4=0
or x=(4−3y)/2
Graph:
Both the lines intersect each other at point (−1,2) and x− axis at A(−3,0) and D(2,0) Which form a triangle, BAD.
Now,
Find the area of triangle BAD:
Area of △BAD=1/2(base×altitude)
=1/2×5×2
=5Â sq.units. Answer!