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Rajan@2021
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Guru

Solve the equations graphically and find the vertices and the area of the triangle formed by these lines and the x-axis: x-y+3=0, 2x+3y-4=0

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An important question from RS Aggarwal, Chapter- Linear equations in which we have given the equations x-y+3=0, 2x+3y-4=0 And we have to solve the equations graphically and also we asked to find the vertices and the area of the triangle formed by these lines and the x-axis

Kindly solve the problem

Chapter 3A, question no 11

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1 Answer

  1. xy+3=0….(1)
    2x+3y4=0……(2)

    Isolate x from equation (1) and find the value of x and y.
    xy+3=0
    or x=y3

       x     y
    3     0
    1     2
        0     3

    Similarly, isolate x from equation (2) and find the values of x and y.
    2x+3y4=0
    or x=(43y)/2

      x      y
      2      0
    1      2
      5    2

    Graph:
    Both the lines intersect each other at point (1,2) and x axis at A(3,0) and D(2,0) Which form a triangle, BAD.

    Now,
    Find the area of triangle BAD:
    Area of BAD=1/2(base×altitude)
    =1/2×5×2
    =5 sq.units. Answer!

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