Show that any positive odd integer is of the form (4m+1) or (4m+3), where m is some integer.

0

This is the basic and conceptual question from real numbers in which we have been asked to prove that any positive odd integer is of the form (4m+1) or (4m+3), where m is some integer.

## Let s be any positive integer.

On dividing s by 4, let m be the quotient and r be the remainder

By Euclid’s division lemma,

s=4m+r, where 0≤r<4

So we have ,s=4m or s=4m+1 or s=4m+2 or s=4m+3.

here 4m,4m+2 are multiples of 2, which revert to even values of s.

again , s=4m+1 or s=4m+3 are odd values of s.

Thus, any positive odd integer is of the form (4m+1) or (4m+3) where s is any odd integer.