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rom each of the two opposite corners of a square of side 8 cm, a quadrant of a circle of radius 1.4 cm is cut. Another circle of radius 4.2 cm is also cut from the center as shown in Fig. Find the area of the remaining (shaded) portion of the square. (Use π = 22/7)

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I would like to give a question which
i could not solve.Rd sharma class 10
maths exercise-15.4 mensuration.

In this question we have to find the area of
the remaining (shaded) portion of the square from each
of the two opposite corners of a square of
side 8 cm, a quadrant of a circle of radius
1.4 cm is cut. Another circle of radius
4.2 cm is also cut from the center.(Use π = 22/7)

 

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1 Answer

  1. Given,

    Side of the square = 8 cm

    Radius of circle = 4.2 cm

    Radius of the quadrant = 1.4 cm

    Thus,

    Area of the shaded potion = Area of square – Area of circle – 2 x Area of the quadrant

    = side2 – πr2 – 2 x ½ πr2

    = 82 – π(4.2)2 – 2 x ½ π(1.4)2

    = 64 – 22/7(4.2 x 4.2) – 22/7(1.4 x 1.4)

    = 64 – 388.08/7 – 21.56/7

    = 5.48 cm2

     

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